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303 lines
6.7 KiB
303 lines
6.7 KiB
#include <stdio.h>
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#include <stdlib.h>
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struct element
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{
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int data;
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struct element * parent;
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struct element * left;
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struct element * right;
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};
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struct element *
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newElement(int data)
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{
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struct element * el = malloc(sizeof(struct element));
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el->data = data;
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el->parent = NULL;
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el->left = NULL;
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el->right = NULL;
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return el;
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}
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/**
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* find element in tree
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*/
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struct element *
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findElement(struct element * tree, int data)
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{
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while (NULL != tree) {
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if (tree->data == data) {
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break;
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}
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if (data < tree->data) {
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tree = tree->left;
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} else {
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tree = tree->right;
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}
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}
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return tree;
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}
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/**
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* insert element in tree
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*/
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void
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insertElement(struct element ** tree, int data)
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{
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struct element * node = *tree;
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if (NULL == node) {
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*tree = newElement(data);
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return;
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}
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while (data != node->data) {
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if (data < node->data) {
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if (NULL == node->left) {
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node->left = newElement(data);
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node->left->parent = node;
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return;
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} else {
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node = node->left;
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}
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} else {
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if (NULL == node->right) {
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node->right = newElement(data);
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node->right->parent = node;
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return;
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} else {
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node = node->right;
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}
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}
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}
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}
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/**
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* delete element from tree
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* here multiple functions are involved....
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* =======================================================================
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*/
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/**
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* find minimum of the right subtree aka leftmost leaf of right subtree
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* aka left in-order successor.
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* We return the parent of the element in the out argument parent.
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* This can be NULL wenn calling.
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*/
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struct element *
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findInOrderSuccessor(struct element * tree)
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{
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struct element * node = tree->right;
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while (NULL != node->left) {
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node = node->left;
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}
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return node;
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}
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void
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deleteElement(struct element ** tree, int data)
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{
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struct element * node = *tree;
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// find the relevant node and it's parent
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while (NULL != node && node->data != data) {
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if (data < node->data) {
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node = node->left;
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} else {
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node = node->right;
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}
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}
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// element not found
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if (NULL == node) {
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return;
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}
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// distinuish 3 cases, where the resolving of each case leads to the
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// precondition of the other.
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// case 1: two children
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if (NULL != node->left && NULL != node->right) {
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struct element * successor = findInOrderSuccessor(node);
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node->data = successor->data;
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node = successor;
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}
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// case 2: one child wither left or right
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if (NULL != node->left) {
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//node->data = node->left->data;
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//node = node->left;
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if (NULL != node->parent) {
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if (node == node->parent->left) {
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node->parent->left = node->left;
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} else {
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node->parent->right = node->left;
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}
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}
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node->left->parent = node->parent;
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}
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if (NULL != node->right) {
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//node->data = node->right->data;
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//node = node->right;
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if (NULL != node->parent) {
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if (node == node->parent->left) {
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node->parent->left = node->right;
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} else {
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node->parent->right = node->right;
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}
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}
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node->right->parent = node->parent;
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}
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// case 3: we are a leaf
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if (NULL != node->parent) {
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if (node == node->parent->left) {
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node->parent->left = NULL;
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} else {
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node->parent->right = NULL;
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}
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}
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if (node == *tree) {
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if (NULL != node->left) {
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*tree = node->left;
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} else if (NULL != node->right) {
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*tree = node->right;
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} else {
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*tree = NULL;
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}
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}
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free(node);
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}
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void
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traverse(struct element * tree, void (*cb)(int, int))
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{
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struct element * previous = tree;
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struct element * node = tree;
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int depth = 1;
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/*
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* I think this has something like O(n+log(n)) on a ballanced
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* tree because I have to traverse back the rightmost leaf to
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* the root to get a break condition.
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*/
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while (node) {
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/*
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* If we come from the right so nothing and go to our
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* next parent.
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*/
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if (previous == node->right) {
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previous = node;
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node = node->parent;
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depth--;
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continue;
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}
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if ((NULL == node->left || previous == node->left)) {
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/*
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* If there are no more elements to the left or we
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* came from the left, process data.
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*/
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cb(node->data, depth);
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previous = node;
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if (NULL != node->right) {
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node = node->right;
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depth++;
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} else {
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node = node->parent;
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depth--;
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}
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} else {
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/*
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* if there are more elements to the left go there.
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*/
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previous = node;
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node = node->left;
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depth++;
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}
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}
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}
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void printElement(int data, int depth)
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{
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int i;
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printf("%02d(%02d)", data, depth);
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for (i=0; i<depth; i++) printf("-");
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puts("");
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}
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/**
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* =======================================================================
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*/
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int
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main(int argc, char * argv[])
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{
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struct element * root = NULL;
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insertElement(&root, 13);
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insertElement(&root, 8);
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insertElement(&root, 16);
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insertElement(&root, 11);
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insertElement(&root, 3);
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insertElement(&root, 9);
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insertElement(&root, 12);
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insertElement(&root, 10);
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/*
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* delete does not work correctly here..
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* luckily I do not need the simple binary trees anymore
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* as I have rbtrees.
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*/
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 8);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 11);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 13);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 3);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 16);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 10);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 9);
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puts("traverse");
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traverse(root, printElement);
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deleteElement(&root, 12);
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puts("traverse");
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traverse(root, printElement);
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return 0;
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}
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// vim: set et ts=4 sw=4:
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